x^2+39x+540=0

Solution for x^2+39x+540=0 equation:

Simplifying
x2 + 39x + 540 = 0

Reorder the terms:
540 + 39x + x2 = 0

Solving
540 + 39x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-540' to each side of the equation.
540 + 39x + -540 + x2 = 0 + -540

Reorder the terms:
540 + -540 + 39x + x2 = 0 + -540

Combine like terms: 540 + -540 = 0
0 + 39x + x2 = 0 + -540
39x + x2 = 0 + -540

Combine like terms: 0 + -540 = -540
39x + x2 = -540

The x term is 39x.  Take half its coefficient (19.5).
Square it (380.25) and add it to both sides.

Add '380.25' to each side of the equation.
39x + 380.25 + x2 = -540 + 380.25

Reorder the terms:
380.25 + 39x + x2 = -540 + 380.25

Combine like terms: -540 + 380.25 = -159.75
380.25 + 39x + x2 = -159.75

Factor a perfect square on the left side:
(x + 19.5)(x + 19.5) = -159.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.